HydForce · mechanical
HydForce hydraulic cylinder force
Know theoretical extension force before selecting a cylinder class for a press or fixture
TECHNICAL UTILITY · HYDRAULIC_CYLINDER_FORCE
Result
A=π(bore/2)²; F=P×A (extension, ignore rod/friction)
How to use this estimate
Ideal hydraulic extension force F=P×A with A=π(bore/2)²; ignores rod area, friction, buckling. Units: psi × in² = lbf (pressure×area). Out of scope as listed on this page. Screening / idealized model only — not a stamped design.
Sources, methodology, and assumptions
Methodology
Ideal hydraulic extension force F=P×A with A=π(bore/2)²; ignores rod area, friction, buckling
Units check
psi × in² = lbf (pressure×area)
Assumptions
Idealized/derived model as scoped; user-supplied inputs.
Out of scope
See MODEL_VALIDITY outOfScope; not a stamped design.
Sources
Unit-context references only — exact model supported by derivation, not org homepages.
Last technically reviewed: 2026-09-11